The population of an insect species in a stand of trees follows the growth cycle of a tree species. The insect population is modeled by y = 40 + 30 sin 6t, where t i the number of years since the...
The population of an insect species in a stand of trees follows the growth cycle of a tree species.
The insect population is modeled by y = 40 + 30 sin 6t, where t i the number of years since the stand was first cut in November, 1920.
a) How often does the insect population reach its max level?
b) When did the population last reach its max?
c) What condition in the stand do you think corresponds with the miniumun insect population?
- print Print
- list Cite
Expert Answers
calendarEducator since 2011
write3,001 answers
starTop subjects are Math, Science, and Business
Given `y=40+30sin6t` where t is the number of years since 1920.
The amplitude of the model is 30 with a midline of 40. Thus the population of insects varies between a maximum of 70 units and a minimum of 10 units.
The period can be found by `p=(2pi)/B` where B is the coefficient of the sine's argument. Thus `p=(2pi)/6=pi/3` . The model has a period of `pi/3` so the insect population has a maximum every `pi/3` years or approximately 1.04 years.
(a) The insect population reaches a maximum approximately every 1.04 years.
(b) At this rate the next population maximum occurs Dec 2012, so the last maximum would have been Dec. 2011
(c) The population cycles approximately yearly.
---------------------------------------------------------------
If you miscopied the problem, as seems likely, and the correct equation was `y=40+30sin( 1/6 t)` then the period is `p=(2pi)/(1/6)=12pi~~37.7` years. Then the last maximum occured in 1995. The population probably maximizes just before the stand is cut again.
Related Questions
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.