Given `y=40+30sin6t` where t is the number of years since 1920.

The amplitude of the model is 30 with a midline of 40. Thus the population of insects varies between a maximum of 70 units and a minimum of 10 units.

The period can be found by `p=(2pi)/B` where B...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

Given `y=40+30sin6t` where t is the number of years since 1920.

The amplitude of the model is 30 with a midline of 40. Thus the population of insects varies between a maximum of 70 units and a minimum of 10 units.

The period can be found by `p=(2pi)/B` where B is the coefficient of the sine's argument. Thus `p=(2pi)/6=pi/3` . The model has a period of `pi/3` so the insect population has a maximum every `pi/3` years or approximately 1.04 years.

(a) The insect population reaches a maximum approximately every 1.04 years.

(b) At this rate the next population maximum occurs Dec 2012, so the last maximum would have been Dec. 2011

(c) The population cycles approximately yearly.

---------------------------------------------------------------

If you miscopied the problem, as seems likely, and the correct equation was `y=40+30sin( 1/6 t)` then the period is `p=(2pi)/(1/6)=12pi~~37.7` years. Then the last maximum occured in 1995. The population probably maximizes just before the stand is cut again.