1 Answer | Add Yours
A population of E.coli bacteria doubles every 15 minutes. The initial population of the bacteria is 500.
An exponential model does not imply the use of 'e'. The general formula for exponential growth is P(t) = P0*(r)^(t/T), where P(t) is the population at time t, P0 is the initial population, r is the positive growth factor and T is the time required for the population to increase by a factor of r.
Here P0 = 500, r = 2 and T = 15.
We need to find P(87).
P(87) = 500*2^(87/15)
The number of bacteria after 87 minutes would be 27857.
We’ve answered 319,180 questions. We can answer yours, too.Ask a question