If a 5 degree polinom (which has 5 roots) has real coefficients and one real zero (3) and four complex zeros, it can be written in the form

`P(x) = A(x-3)(X^2+Bx+C)(X^2+Dx+E)`

where `P_1(x) =X^2+Bx+C` and `P_2(x)=X^2+Dx+E` both have complex conjugate roots. Thus in the problem since `-5i` and `-5+i` are not complex conjugated it means each are a root of `P_1(x)` and `P_2(x)` . Therefore the other two roots that are missing are their complex conjugate `+5i` and `-5-i` .

**The correct answer is B) `+5i` and `-5-i` **

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now