point (-6,-8) lies on the terminal terminal arm of an angle `theta` in standard position. Determine the exact value of sin`theta` plus tan`theta`(sin+tan) ` ` Sin `theta` = Y/R Cos `theta` = X/R Tan `theta` = Y/X
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Luca B.
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You need to evaluate sin theta such that:
`sin theta = y/R`
You may evaluate ` R` using the pythagorean theorem such that:
`R = sqrt(x^2 + y^2) => R = sqrt((-6)^2 + (-8)^2)`
`R = sqrt(36 + 64) => R = 10`
Substituting -8 for y and 10 for R yields:
`sin theta = x/R => sin theta = -8/10 => sin theta = -4/5 =>...
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