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point (-6,-8) lies on the terminal terminal arm of an angle `theta` in standard position. Determine the exact value of sin`theta` plus tan`theta`(sin+tan) ` ` Sin `theta` = Y/R  Cos `theta` = X/R  Tan `theta` = Y/X

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You need to evaluate sin theta such that:

`sin theta = y/R`

You may evaluate ` R` using the pythagorean theorem such that:

`R = sqrt(x^2 + y^2) => R = sqrt((-6)^2 + (-8)^2)`

`R = sqrt(36 + 64) => R = 10`

Substituting -8 for y and 10 for R yields:

`sin theta = x/R => sin theta = -8/10 => sin theta = -4/5 =>...

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