# The numerator of a fraction is 5 less than its denominator. If 1 is added to the numerator and to the denominator, the new fraction is `2/3` . Find the fraction. Please help as I don't understand.

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Suppose the denominator is x,

then the numerator is x-5, since numerator is 5 less than denominator.

And the required fraction is (x-5)/x

If we use the given scenario, when 1 is added to the numerator and denominator , the fraction becomes 2/3

Adding 1 to both numerator and denominator:

(x-5+1)/(x+1) = 2/3

or 3 (x-4) = 2(x+1)

or 3x-12 = 2x+2

or 3x-2x = 2+12 that is x =14 and x-5 = 9

Thus the required fraction (x-5)/x = **9/14**.

check: adding 1 to both numerator and denominator, we get (9+1)/(14+1) = 1015 = 2/3, which is given information.

Thus the answer is **9/14**.

Start by writing any missing number as a variable.

If “The numerator of the fraction is five less than the denominator,” then you could write the denominator as **x** and the numerator as **x-5.**

That means that the missing fraction is **(x-5)/x**.

Now you must “add one to the numerator and denominator.”

So the new fraction is **(x-5+1)/9x+1)** or** (x-4)/(x+1)**.

According to the question, this equals **2/3**.

Therefore, we can set up an equation: **(x-4)/(x+1) = 2/3**.

To solve, cross multiply: **3(x-4) = 2(x+1)**

Solve for **x**:

**3x-12 = 2x+2**

**x=14**

Remember, this is only x. You must still plug it into the fraction: **(14-5)/14**.

Simplify: **(9/14)**.