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Suppose the denominator is x,
then the numerator is x-5, since numerator is 5 less than denominator.
And the required fraction is (x-5)/x
If we use the given scenario, when 1 is added to the numerator and denominator , the fraction becomes 2/3
Adding 1 to both numerator and denominator:
(x-5+1)/(x+1) = 2/3
or 3 (x-4) = 2(x+1)
or 3x-12 = 2x+2
or 3x-2x = 2+12 that is x =14 and x-5 = 9
Thus the required fraction (x-5)/x = 9/14.
check: adding 1 to both numerator and denominator, we get (9+1)/(14+1) = 1015 = 2/3, which is given information.
Thus the answer is 9/14.
Start by writing any missing number as a variable.
If “The numerator of the fraction is five less than the denominator,” then you could write the denominator as x and the numerator as x-5.
That means that the missing fraction is (x-5)/x.
Now you must “add one to the numerator and denominator.”
So the new fraction is (x-5+1)/9x+1) or (x-4)/(x+1).
According to the question, this equals 2/3.
Therefore, we can set up an equation: (x-4)/(x+1) = 2/3.
To solve, cross multiply: 3(x-4) = 2(x+1)
Solve for x:
3x-12 = 2x+2
Remember, this is only x. You must still plug it into the fraction: (14-5)/14.
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