# Pls answer each part clearly with steps that are clear as I don't get the velocit part and changing it back into metres pls explain with a written procedure for each step and pls write about how u...

Pls answer each part clearly with steps that are clear as I don't get the velocit part and changing it back into metres

pls explain with a written procedure for each step and pls write about how u did it for parts a b c and d

thankyou

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jerichorayel | College Teacher | (Level 2) Senior Educator

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The graph showed the relationship with the displacement with the time it took for it to happen. It is hard to get the linear equation since so what we have to do is to trace the graph with the corresponding value in the question/s. (See attached image)

(a) At 10 seconds, the distance is at 11 m.

(b) The displacement is the change in the original position with the current location.

Displacement = final distance - initial distance

Displacement = 11 - 0 = 11m

(c) Velocity = change in distance/ change in time = 11/10 = 1.1 m/s

Next we need to get approximate values on the graph:

Time (x)       2.5 | 5 | 10 |

Distance (y)     5 | 7 | 11 |

Get the value of slope

m = y2-y1 / x2-x1

m = 11-7/10-5 = 0.8

You can get the value of distance at 8 sec (d). You can use any ordered pairs above. In this case we will use (5,7)

Let: Y2 = 7 X2 = 5

Y1 = ? X1 = 8

m = y2-y1 / x2-x1

0.8 = 7-y1 / 5-8

y1 = 9.4

Velocity = 9.4/8 = 1.175 m/s -> (d)

Do the same method for item (e) @ 30 seconds

Let: Y2 = 7 X2 = 5

Y1 = ? X1 = 30

m = y2-y1 / x2-x1

0.8 = 7-y1/5-30

y1 = 27

Velocity = 27/30 = 0.9 m/s -> (e)

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