How do you find the derivative of : 3 - (3/(5x)) ?

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justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

We have to find the derivative of : y = 3 - (3/(5x))

y = 3 - (3/(5x))

y' = [3 - (3/(5x))]'

=> y' = [3]' - [(3/5)*(1/x)]'

The derivative of a constant term is 0 and that of x^n is n*x^(n-1)

=> y' = 0 - (3/5)(-1)*x^(-1-1)

=> y' = (3/5)/x^2

=> y' = 3/(5*x^2)

The derivative of 3 - (3/(5x)) is 3/(5*x^2)

sushila69's profile pic

sushila69 | Student, Undergraduate | (Level 1) eNoter

Posted on

We have to find the derivative of:

y = 3 - (3/5x) = 3 - (3/5).x^-1

Hence,

Derivative of  y = dy/dx   and  d(3)/dx = (3)'  and

d(x^-1)/dx =  - x^-2

So,  dy/dx =  (3)' - (3/5)(-x^-2)

Now,  (3)' = 0.00

Hence,  dy/dx =  3/(5x^2)

 

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