Find an equation of the line that is parallel to `y=3/4 x -1` and passes through the point (4,0). Find an equation of the line that is perpendicular to `y=x+4` and through the point (-7, 1).

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An equation paralle to `y= 3/4x-1` and passes through the point (4,0).  Since the equation is written in slope intercept form the line has a slope of `3/4` .

In order to be parallel the line must havet he same slope, `3/4.`

Use point slope form `y - y_(1)= m(x-x_(1))` , to write the equation of the line.

`y - 0 = 3/4(x-4) rArr y = 3/4x - 3`

A line perpendicular to `y = x+4` , must have a slope of `-1` as this is the opposite reciprocal of the line's slope of 1.

Again use point slope form to write the equation as it passes through the point (-7, 1)

`y-1=-1(x-(-7))`

`y - 1 = -1(x+7)`

`y = -1x - 7 + 1`

`y = -x -6`

The solution to part 1 is `y = 3/4x - 3` and the solution to part 2 is` y = -x-6` .

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If two lines are parallel, they have the same slope.

The slope of  `y=3/4 x -1`   is    `3/4`

So we want a line with slope   `3/4` , that goes through the point  `(4,0)`

We know the slope, we want to find the y-intercept:

`y=3/4 x + b`

`0 = 3/4 (4) + b`

`0=3+b`

`-3=b`

So:  `y=3/4 x - 3`

This is the equation of the line that is parallel to `y=3/4 x -1` that passes through (4,0)

Two lines are perpendicular if you multiply their slopes and get -1.  In other words, you want the "negative reciprocal"

`y=x+4`

This line has slope = 1.

So a perpendicular line would have slope = -1.

`y=-1 x + b=-x + b`

Now we need to find the y-intercept.

Plug in (-7,1)

`1=-(-7)+b`

`1=7+b`

`-6=b`

so:

`y=-x-6`

This is the line that is perpendicular to `y=x+4` and passes through the point (-7,1)

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