What is the solution of 3x + 8y = 92 and 2x - 6y = 16.
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The set of linear equations 3x + 8y = 92 and 2x - 6y = 16 have to be solved.
3x + 8y = 92 ...(1)
2x - 6y = 16 ...(2)
2x - 6y = 16
=> x = 8 + 3y
Substitute in (1)
=> 3(8 + 3y) + 8y = 92
=> 24 + 9y + 8y = 92
=> 17y = 68
=> y = 4
x = 20
The solution of the given set of equations is x = 20, y = 4
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3x + 8y = 92
2x - 6y = 16
First multiply everything in the top equation by 2 and everything in the bottom equation by 3
By doing that, you should get
6x + 16y = 184
6x - 18y = 48 now subtract 6x with 6x (which means also subtract 16y with 18y and 184 with 48)
By subtracting, you should get
34y = 136 now divide both sides by 34
By dividing, you should get
y = 4 which is your answer for " y "
Now plug 4 into one of the equation
2x - 6 ( 4 ) = 16 Multiply -6 with 4
By multiplying, you should get
2x -24 = 16 now add 24 on both sides
By adding, you should get
2x = 40 now divide both sides by 2
By dividing, you should get
x = 20 which is your answer for " x "
So your answer is x = 20 ; y = 4
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