# Please explain how to solve for the acceleration of the following. A train starts at rest and accelerates to 54 km/hr in 10 seconds.I know that you subtract the final velocity minus the initial (54...

Please explain how to solve for the acceleration of the following. A train starts at rest and accelerates to 54 km/hr in 10 seconds.

I know that you subtract the final velocity minus the initial (54 m/s- o m/s).

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Acceleration is the rate of change of velocity. It is expressed in the units (m/s)/s or m/s^2.

If the initial velocity v0 and the final velocity vf after a duration of time d is given we can obtain the acceleration during the interval d as (vf - v0)/d.

In the problem, the train starts at rest and reaches a velocity 54 km/hr in 10 sec.

You have to convert all the values to the same units before any calculations can be done. Ideally use the SI units. This gives the initial velocity as 0 m/s. After 10 seconds the velocity is 54 km/hr or 54*1000/60*60 = 15 m/s

The acceleration of the train during the 10 seconds was (15 - 0)/10 = 15 m/s^2.