# please could you explain it step by steps? Thank you The density of water varies slightly with temperature. As it is heated it becomes less dense as the average distance between the molecules...

please could you explain it step by steps?

Thank you

The density of water varies slightly with temperature. As it is heated it becomes less dense as the average distance between the molecules increases with temperature. If the density of warm water is measured to be **
0.994 g/cm ^{3}** what volume

**V**would

**250 kg**of water at this temperature occupy?

*V =*m

^{3}(decimal number to

**3**significant figures)

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### 1 Answer

Density = mass/volume.

If the density of warm water is .9850994 g/cm3 and you want to find the volume of 250 kg of water at that same temperature, and therefore, that same density, then volume would = density/mass.

d=m/v

multiply both sides by v, and you get:

dv = m

then divide both sides by d, to get the formula for volume:

v=m/d

Since water is about 1 gm/cm3, I'm assuming that you mean this particular density is .985 g/ .994 cm3. Now, we plug the numbers into the equation:

V = 250 kg/ .985g/.994cm3

First, let's change kg to g and change cm3 to m3 since your answer calls for that. 1 cm3 = 10^-6 m3.

V = 250,000g / .985g/.000000994 m3.

Dividing by a fraction, we then multiply 250,000 g by the reciprocal of that fraction.

V = 250,000g * .000000994m3/.985g

= .252 m3