A plastic-foam container used as a picnic cooler contains a block of ice at 0 C. If 316 g of ice melts, how much heat passes through the walls of the container?
The latent heat of ice is 3.33 × 10^5 J/kg. Answer in units of J
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The atoms of water in the liquid state are arranged in a less orderly state that the atoms of water in the solid state. To covert solid ice to liquid water, heat has to be added. It is given that the latent heat of fusion is 3.33*10^5 J/kg. This means that 3.33*10^5 J of heat has to be added to a kilogram of ice at 0 C to convert it to water at 0 C.
The plastic-foam container used as a picnic cooler contains a block of ice at 0 C that weighs 316 g = 0.316 kg. To melt this to water at 0 C, the amount of heat that is required from to pass through the walls of the container from outside is 3.33*10^5*.316 = 1.05228*10^5 J
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