Physics Velocity:A glider flies southeast at 320 degrees at 25 km/h...A glider flies southeast at 320 degrees at 25 km.h.  A wind blows a 12.0 km/h from 15 degrees south of west.  What is the...

Physics Velocity:A glider flies southeast at 320 degrees at 25 km/h...

A glider flies southeast at 320 degrees at 25 km.h.  A wind blows a 12.0 km/h from 15 degrees south of west.  What is the new velocity of the glider with respect to the ground in standard position

Asked on by hurdpeter

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ndnordic | High School Teacher | (Level 2) Associate Educator

Posted on

You have two vectors which you need to add. To add them, you first need to resolve them into their x-and y-components.

320 degrees is equivalent to 40 degrees S of W for the glider.  The wind is 15 degrees S of west also, so the two vectors are relatively in the same direction and the x- and y- components will be added to find the resultant velocity (speed + angle)

Vector 1:  glider

sin 40 = y/25 and cos 40 = x/25

Vector 2: wind

sin 15 = y/12 and cos 15 = x/12

Solve to find the vector components and add the x- and y-components.

Once you have the two components, use Pythagorean Theorem to find the resultant vector speed of the glider.  To find the resultant angle, use inverse tangent of the y-value over the x-value.

 

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