Physics Velocity:A glider flies southeast at 320 degrees at 25 km/h...
A glider flies southeast at 320 degrees at 25 km.h. A wind blows a 12.0 km/h from 15 degrees south of west. What is the new velocity of the glider with respect to the ground in standard position
You have two vectors which you need to add. To add them, you first need to resolve them into their x-and y-components.
320 degrees is equivalent to 40 degrees S of W for the glider. The wind is 15 degrees S of west also, so the two vectors are relatively in the same direction and the x- and y- components will be added to find the resultant velocity (speed + angle)
Vector 1: glider
sin 40 = y/25 and cos 40 = x/25
Vector 2: wind
sin 15 = y/12 and cos 15 = x/12
Solve to find the vector components and add the x- and y-components.
Once you have the two components, use Pythagorean Theorem to find the resultant vector speed of the glider. To find the resultant angle, use inverse tangent of the y-value over the x-value.