Physics Velocity:A glider flies southeast at 320 degrees at 25 km/h...
A glider flies southeast at 320 degrees at 25 km.h. A wind blows a 12.0 km/h from 15 degrees south of west. What is the new velocity of the glider with respect to the ground in standard position
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You have two vectors which you need to add. To add them, you first need to resolve them into their x-and y-components.
320 degrees is equivalent to 40 degrees S of W for the glider. The wind is 15 degrees S of west also, so the two vectors are relatively in the same direction and the x- and y- components will be added to find the resultant velocity (speed + angle)
Vector 1: glider
sin 40 = y/25 and cos 40 = x/25
Vector 2: wind
sin 15 = y/12 and cos 15 = x/12
Solve to find the vector components and add the x- and y-components.
Once you have the two components, use Pythagorean Theorem to find the resultant vector speed of the glider. To find the resultant angle, use inverse tangent of the y-value over the x-value.
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