# What is the potential energy of a crate of 500N at the edge of a ramp 5 m long inclined at 20 degree to the horizontal? The potential energy that the crate has on the ramp is due to the gravitational force of attraction between the crate and the Earth. It is given by m*g*h, where m is the mass of the crate, g is the acceleration due to gravity and h is the height of the...

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The potential energy that the crate has on the ramp is due to the gravitational force of attraction between the crate and the Earth. It is given by m*g*h, where m is the mass of the crate, g is the acceleration due to gravity and h is the height of the crate.

Here we are given m*g as 500N

The length of the ramp is 5 m and it is inclined at 20 degrees with the horizontal. This can be used to find the height of an object at the edge of the ramp by 5* sin 20.

The potential energy of the crate due to the gravitational force is therefore 500*5* sin 20

=> 2500 * sin 20

=> 855.05 J

The required potential energy is 855.05 J

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