The half life of C-14 is 5730 years. In 5730 years, the amount of C-14 decreases to 1/2 the initial amount. In n*5730 years, the amount if C-14 left is given by (1/2)^n

Let the age of the fragment in the cave be n years. It is given that the fragment has 0.21 times as much C-14 as what the atmosphere had.

This gives us : 0.21 = (1/2)^n

Take the logarithm of both the sides

=> log 0.21 = log [(1/2) ^n]

=> log 0.21 = n * log (1/2)

=> n = log 0.21 / log 0.5

=> n = 2.2515

The age of the fragment is n* 5730 = 2.2515* 5730 = 12901 years.

**The required age of the fragment is approximately 12901 years.**

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