The angular momentum of a body having mass `m` with respect to an axis is by definition given the the vectorial product between its position vector `r` measured perpendicular from that axis and its linear momentum `p =m*v` . Therefore,

L = rx p = rx (mv) =m*(rxv)

where bold...

## Check Out

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

The angular momentum of a body having mass `m` with respect to an axis is by definition given the the vectorial product between its position vector `r` measured perpendicular from that axis and its linear momentum `p =m*v` . Therefore,

L = rx p = rx (mv) =m*(rxv)

where bold letters represent vector quantities and x is the vector product. Since the vector product is represented by a determinant we can write for the angular momentum the relation:

`L =4.1*(-3.5*hatx +1.4*haty +0*hatz) xx (-2.0*hatx -6.3haty+0hatz)`

`L =4.1*|[hatx, haty, hatz],[-3.5,1.4,0],[-2,-6.3,0]| =4.1*24.85*hatz =101.885*hatz ((kg*m^2)/s)`

**The magnitude of the angular momentum is `L=101.885 ((kg*m^2/s)` and its direction is toward the positive sense of z axis**