A person with body resistance between his hands of 10KΩ accidentally grasps the terminal of a 14-KV power supply.If the internal resistance of the power supply is 2000Ω, what is the current...

A person with body resistance between his hands of 10KΩ accidentally grasps the terminal of a 14-KV power supply.

If the internal resistance of the power supply is 2000Ω, what is the current through the person’s body and the power dissipated in his body?

Expert Answers
justaguide eNotes educator| Certified Educator

The current 'I' that flows when a voltage 'V' is applied across a resistor 'R' is given by I = V/R.

Here, the total resistance is 10000 + 2000 = 12000 ohm.

The voltage applied across this resistance is 14000 V.

This makes a current equal to 14000/12000 = 7/6 amp flow through the person's body.

The power P dissipated is given as P = V^2/R

We are only interested in the power dissipated through the person's body. This is given by (14000)^2/10000 = 19600 W

The current flowing through the resistance is 7/6 amp and the power dissipated through the person's body is 19600 W

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