If a person produces 0.050 mole of excess HCl in the stomach, how many moles of Mg(OH)2 are needed to neutralize this excess HCl?

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`Mg(OH)_2+2HCl rarr MgCl_2+2H_2O`

Mole ratio

`Mg(OH)_2:HCl = 1:2`

 

There for to react with 1 HCl mole we need 0.5 moles of `Mg(OH)_2`

`Mg(OH)_2` needed to neutralize HCl `= 0.05/2 = 0.025`

 

So we need 0.025moles of `Mg(OH)_2` to neutralize HCl.

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