# A person in a certain family eats 709.5 lb of fruits and vegetables in a year. What is the average consumption in one day?

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Take note that average is defined as the sum of all the given elements divided by the total number of elements.

Applying this to our problem, we would have:

Average daily consumption `= ( t ot a l n umbe r of pounds)/( t ot a l n umbe r of periods)`

Since we are given with the total consumption in a year, then the total number of periods is 365 days.

Average daily consumption ` = 709.5/365=1.9`

**Therefore, the family's average consumption of fruits and vegetables in one day is 1.9 lb.**

If the family eats 709.5 lbs of fruits and vegetables a year you would have to divide that by 365 to get the consumption per day. There are 365 days in one year, so by dividing the amount of fruits and vegetables eaten per yer by 365 you will get the amount per day. 709.5 divided by 365 days equals an average of 1.94 fruits and vegetables per day.

709.5 lb of fruits and vegetables every year and here are 365 days in a year. so divide 709.5/365 in order to get how many pounds of fruits and vegetables in a day which is equal to 1.94 pounds.

Because there are 365 days in a year, to find the average daily consumption:

Divide yearly consumption by number of days.

709.5 `-:` 365 = 1.9438356 `~~ ` 1.94 pounds

A person in a certain family eats 709.5 lb of fruits and vegetables in a year. What is the average consumption in one day?

First we need to know how many days there are in a year. There are 365 days in a year. The word problem is asking us to find how much a person eats per a day if they eat 709.5 lb of fruits and vegetables in a year. In order to find that we would have to use division, so divide 709.5 by 365

709.5 ÷ 365 = 1.94

So that person eats approximately 1.94 pounds of fruits and vegetables a day.

This is a simple question which involves the following calculations :-

No of days = 365

Average daily consumption `709.5/365`

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`=1.9438356`

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