Permutations & Combinations ? 4C2 ? 11C5?
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You should use factorial formula for combinations such that:
`C_n^k = (n!)/(k!(n-k)!)`
Reasoning by analogy yields:
`C_4^2 = (4!)/(2!(4-2)!) => C_4^2 = (4!)/(2!2!)`
You may write 4! such that:
`4! = 1*2*3*4 = 2!*3*4`
`C_4^2 = (2!*3*4)/(2!2!) => C_4^2 = (3*4)/(2!) => C_4^2 = 12/2`
`C_4^2 = 6`
You may evaluate `C_11^5 ` using the above factorial formula such that:
`C_11^5 = (11!)/(5!(11-5)!) => C_11^5 = (11!)/(5!*6!)`
`C_11^5 = (6!*7*8*9*10*11)/(1*2*3*4*5*6!)`
`C_11^5 = (7*3*2*11) => C_11^5 = 462`
Hence, evaluating the given combinations using factorial formula yields `C_4^2 = 6` and `C_11^5 = 462` .
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