The perimeter of rectrangular field is 172 meters. Double the width is 4 meters more than the length. Find the area of the field.I would like to know what is the equation to use to solve the problem.
The perimeter of rectangular field is 172 meters.
Let the width of the field be W = X. Twice the width of the field is 4 more than the length. The length is equal to L = 2*X - 4.
The perimeter of the rectangular field is 2*(W + L)
=> 2*(X + 2*X - 4)
=> 6x - 8
6X - 8 = 172
=> X = 30
The area of the field is W*L = 30*56 = 1680 square meters.