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Given the perimeter of a rectangle is 224, we need to find the area.
First we will find the length of the sides.
==> Let the length be L and the width be W.
Then the perimeter is P = 2L + 2w = 224
We will divide by 2.
==> L + w = 112............(1)
Now we are given that L= 3w
==> 3w + w = 112
==> 4w = 112
==> w =28
==> L= 84
Now we will calculate the area.
==> A= L*w = 84*28 = 2352
Then the area of the rectangle is 2,352 cm^2
For a rectangle with sides W and L, the perimeter is equal to 2*(W + L) and the area of the rectangle is W*L.
Let the width of the rectangle be W. It is given that the length is 3 times the width or L = 3*W.
The perimeter of the rectangle is 2*(L+W) = 2*(3W + W) = 8W = 224
W = 28
L = 84
The area of the rectangle is W*L = 28*84 = 2352
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