In Cambridge, England, a seconds pendulum is 0.9942 m long. What is the free-fall acceleration in Cambridge? (Use 4 significant figures in your answer.) A pendulum that moves through its equilibrium position once every 1.000 s is sometimes called a seconds pendulum. Answer in  m/s2  

Expert Answers

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If the pendulum passes its equilibrium position every 1 second.

It's period is 2 seconds. (for over one wavelength you have two equilibrium positions)

the equation for period is,

T = 2pi * sqrt(L/g)

where L = 0.9942 m

2 = 2 *pi*sqrt(0.9942/g)

g = 9.812 ms-2 (for four significant figures)

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