If the pendulum passes its equilibrium position every 1 second.

It's period is 2 seconds. (for over one wavelength you have two equilibrium positions)

the equation for period is,

T = 2pi * sqrt(L/g)

where L = 0.9942 m

2 = 2 *pi*sqrt(0.9942/g)

g = 9.812 ms-2 (for four significant figures)

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now