In Cambridge, England, a seconds pendulum is 0.9942 m long. What is the free-fall acceleration in Cambridge? (Use 4 significant figures in your answer.)
A pendulum that moves through its equilibrium position once every 1.000 s is sometimes called a seconds pendulum.
Answer in m/s2
If the pendulum passes its equilibrium position every 1 second.
It's period is 2 seconds. (for over one wavelength you have two equilibrium positions)
the equation for period is,
T = 2pi * sqrt(L/g)
where L = 0.9942 m
2 = 2 *pi*sqrt(0.9942/g)
g = 9.812 ms-2 (for four significant figures)