In peas, tall plants are dominant to short plants. Do a Punnett Square to show genotypes and phenotypes for heterozygous tall times heterozygous tall.
I have attempted it and got PP, Pp for the genotypes. I got 50% tall and 50% short for the phenotypes. I am just wanting to know if I am correct and if I am going in the correct direction with solving punnett squares.Thank you to anyone in advance that helps check my answer!
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When crossing two heterozygous tall pea plants, you must first figure out which alleles each parent has. Heterozygous means both alleles for a trait are different. In pea plants, there are two alleles for the trait of height--Tall and Short. Since tall is dominant to short, we can represent the allele for tall as T and the allele for short as t. Since the parents are heterozygous tall, their genotypes are each Tt. When Tt is crossed with Tt in a Punnett square, the following results are obtained.
25% have the genotype TT or homozygous tall. 50% have the genotype Tt or heterozygous tall. 25% have the genotype tt or homozygous short.
The phenotype or observable trait you see is 75% appear tall and 25% appear short. Remember that anytime the dominant trait is present with the recessive trait in an individual, the dominant trait(T) will be expressed and the recessive trait(t) will remain hidden.
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