In peas, tall plants are dominant to short plants. Do a Punnett Square to show genotypes and phenotypes for heterozygous tall times heterozygous tall.
I have attempted it and got PP, Pp for the genotypes. I got 50% tall and 50% short for the phenotypes. I am just wanting to know if I am correct and if I am going in the correct direction with solving punnett squares.Thank you to anyone in advance that helps check my answer!
When crossing two heterozygous tall pea plants, you must first figure out which alleles each parent has. Heterozygous means both alleles for a trait are different. In pea plants, there are two alleles for the trait of height--Tall and Short. Since tall is dominant to short, we can represent the allele for tall as T and the allele for short as t. Since the parents are heterozygous tall, their genotypes are each Tt. When Tt is crossed with Tt in a Punnett square, the following results are obtained.
25% have the genotype TT or homozygous tall. 50% have the genotype Tt or heterozygous tall. 25% have the genotype tt or homozygous short.
The phenotype or observable trait you see is 75% appear tall and 25% appear short. Remember that anytime the dominant trait is present with the recessive trait in an individual, the dominant trait(T) will be expressed and the recessive trait(t) will remain hidden.