# Passes through (6, -5), perpendicluar to the line whose equation is 3x - 1/5 y = 3. Write an equation in slope-intercept form for the line that satisfies each set of conditions.

The given equation of the line is: 3x-(1/5)y=3

The given coordinate point is: (x1,y1) = (6,-5)

Rewrite the given equation in Slope-Intercept Form, in other words, solve for
"y":

3x-(1/5)y=3

-(1/5)y=-3x+3

y=15x-15

The slope of the given line is: 15

The slope of its perpendicular line it's the reciprocal of the original slope with opposite sign: -(1/15)

Use the Slope-Intercept Form, y-y1=m(x-x1) and solve for "y" using m= -(1/15) and the original coordinate point (x1,y1)=(6,-5)

y-y1=m(x-x1)

y-(-5)=-(1/15)(x-6)

y+5=-(1/15)x+(2/5)

y=-(1/15)x-(23/5)

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