# Passes through (-3, -1), parallel to the line that passes through (3, 3) and (0, 6). Write an equation in slope-intercept form for the line that satisfies each set of conditions.

### Textbook Question

Chapter 2, 2.4 - Problem 38 - Glencoe Algebra 2 (1st Edition, McGraw-Hill Education).
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Given

a line L1 (let us assume) passes through (-3, -1) and is parallel to the line L2 (let us assume) that passes through (3, 3) and (0, 6).

we need to find the equation of L1?

sol:

First we need to find the slope of the line L2 that passes through (3, 3) and (0, 6).

m_2 = (6-3) / (0-3) = 3/ -3 = -1

as the line L1 and L2 are parallel so their slopes are equal

so the slope of the line L1 is m = -1 and it passes

through the point (-3, -1).

the line equation is given as the slope-intercept from

y= mx +b

=>y = (-1)x+b------------(1)

as the line (1) passes through the point (-3, -1) we get the value of b on substituting as follows

-1 = (-1)(-3) +b

=> b = -1-3 = -4

so the equation of the line from  (1) is

y = -x -4 is the sloution