Passes through (-2, -3) and (0, 0). Write an equation in slope-intercept form for the line that satisfies each set of conditions.

Textbook Question

Chapter 2, 2.4 - Problem 32 - Glencoe Algebra 2 (1st Edition, McGraw-Hill Education).
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kspcr111 | In Training Educator

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Given the points are

`(x_1,y_1) =(-2,-3)`

and

`(x_2,y_2) =(0,0)`

the slope of the line passing through the points is given as 

`m = (y_2 - y_1)/(x_2 - x_1)`

    `= (0 - (-3))/(0-(-2))`

   ` = 3/2`

so the slope is `3/2`

as the

 slope `m= 3/2`

and the line passes through the point `(x,y)= (0, 0)`

the slope-intercept form of a line is

`y= mx+b`

from the above we know `m = 3/2` , so the line equation is 

`y= (3/2)x+b` --------------(1)

we need to find the value of b , as the line passes through the point

(x,y)= (0, 0 ) , then on substituting we get

`0 =(3/2)*(0)+b`

=> `b = 0`

so the equation of the line is

`y = (3/2)x`

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