# ``passes through `(-2, 2)`, parallel to a line whose slope is `-1` Graph the line that satisfies each set of conditions.

### Textbook Question

Chapter 2, 2.3 - Problem 43 - Glencoe Algebra 2 (1st Edition, McGraw-Hill Education).
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kspcr111 | In Training Educator

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The line which we needed is perpendicular to a line whose slope is (-1)  .

the product of the slopes of two lines which are perpendicular is equal to  -1

let the slope of the line which we need to find be m_1 and the slope of the other line  be m_2 = -1

so ,

`m_1 * m_2 = -1`

=> `m_1 = -1/(m_2) = -1 /(-1) = 1`

so , `m_1 = 1`

and the line of slope `m_1` passes through the point `(-2,2)`

then the line is

`y = mx+c`

=> `y = (1)x +c`

as it passes through `(x,y)=(-2,2)` so

=>  `2= (1)(-2) +c`

=>` 2= -2 +c`

=> `2+2 = c`

=> `c = 4`

so the equation of the line is `y= x+ 4` and the graph plotted is as follows in the attachments. the point `(-2,2)` is spotted with a blue dot.

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