a particle moves with the position function s = t^4 - 4t^3 - 20t^2 + 20t    t  is greater than or equal to 0 at what time does the particle have a velocity of 20m/s? at what time is the accelleration 0? what is the significance of this value of t?

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`s(t) = t^4 - 4t^3 - 20t^2 + 20t`

The velocity function is given by the derivative of position function.

`v(t) = (ds(t))/dt`

`v(t) = 4t^3-12t^2-40t+20`


When the particle velocity is 20 then;

`v(t) = 20`

`4t^3-12t^2-40t+20 = 20`


(The entire section contains 142 words.)

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