a. For the Ratio Test, we need to examine the ratio of (k+1)-th coefficient to k-th coefficient, here it is

`(1/((k+1)!)) /(1/(k!)) = (k!)/((k+1)!) = 1/(k+1).`

The limit of this ratio is 0, therefore the power series converges everywhere (and there are no endpoints to check).

b. To determine the function to which the series converges, recall the definition of the Taylor series (with the center at  `x=0` ). For a function `f(x)` its Taylor series is   `sum_(k=0)^oo f^(k)(0) x^k/k!`

Our series is   `sum_(k=0)^oo x^(k+1)/(k!) = x sum_(k=0)^oo x^k/(k!) = x e^x,`

because  `(e^x)^((k)) = e^x`  and  `(e^x)^((k))(0) = 1.`