sketch: x^2 = 8Y. indicate its vertex focus, directrix Parabola problem

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rcmath | High School Teacher | (Level 1) Associate Educator

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`x^2=8y=>y=1/8x^2`

Vertex: x=-b/2a=>x=0, plug it in the original function, y=0. Hence vertex (0,0)

Focus:To find the p, we set 4p=coefecient of the unsquare part (use the given equation before we rewrote it) 4p=8 => p=2 => Focus is two units above the vertex => Focus (0,2).

Directrix: is 2 units below the parabola => y=-2

 

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