1 Answer | Add Yours
`(p+7)/p + (2p)/(p+3)`
Multiply each term by a factor that will equate both the denominators. Here, both terms need a denominator of p(p+3).
`((p+3)/(p+3))* (p+7)/p + (2p)/(p+3) (p/p)`
`((p+3)(p+7))/(p(p+3)) + ((2p)(p))/(p(p+3))`
Now let's simplify the numerators in order to add since we have a common denominator.
Use FOIL for the first terms.
`((p^2 +10p+21) +2p^2)/(p(p+3))`
Combine like terms in the numerator.
`(3p^2 +10p +21)/ (p(p+3))`
We’ve answered 320,004 questions. We can answer yours, too.Ask a question