Oxidation and reduction equations: Cd + NiO = CdO + Ni. Write the balanced oxidation 1/2 reaction equation and balanced reduction 1/2 reaction. Be sure to include the proper # of electrons in the...

Oxidation and reduction equations:

Cd + NiO = CdO + Ni. Write the balanced oxidation 1/2 reaction equation and balanced reduction 1/2 reaction. Be sure to include the proper # of electrons in the equations.

I know that Loss of electrons = oxidation and gaining of electrons= reduction but i have no idea what this is asking.

Asked on by wunderlust

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bandmanjoe | Middle School Teacher | (Level 2) Senior Educator

Posted on

The equation you are working with is known as an oxidation-reduction equation.  Basically, the part of the equation that donates electrons, cadmium, is known as the reducing agent.  It is willing to donate 2 electrons to the nickel oxide.  The nickel oxide is called the oxidizing agent, for two reasons: it is accepting the 2 electrons cadmium is offering and giving over oxygen to cadmium to bind to in order to make cadmium oxide.  The two half equations should look something like this:

Cd --->  (Cd++)  +  2e-   (this is the reducing agent giving up electrons)

NiO  +  2e-  --->  Ni  +  (O--)  (this is the oxidizing agent providing the oxygen)

The 2 half equations add up to give the net equation given in the question.  The 2 electrons from each half reaction cancel each other out.

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