Question

the one-to-one functions g and h are defined as follows. g={(-4, -5), (1, 2), (7,1), (8, 5)} 
find the following: g^-1(1)=
-----
h^-1(x)= (h * h^-1) (5)=

Accepted Answer

In this question we need to find g^(-1) and h^(-1) , which are the inverse functions of the functions g and h, respectively.
The function g is given as a set of ordered pairs. To create inverse function g^(-1) , simply exchange x and y, or first and second coordinate, for each pair:
g^(-1) = {(-5, -4), (2, 1), (1, 7), (5, 8)}
Now we see that the value of g^(-1) of 1 is the second coordinate of the pair where the first coordinate is 1:
g^(-1) (1) = 7
Function h is given as a formula: h(x) = 2x + 3. To find inverse function, exchange x and y in the equation y = 2x + 3 and solve for y:
x= 2y + 3
2y = x - 3
y = (x-3)/2
This is the inverse function of h(x):
h^(-1)(x) = (x-3)/2
The last expression is a composition of function h and its inverse:
(h*h^(-1))(5) = h(h^(-1)(5))
First, evaluate the innermost parenthesis:
h^(-1)(5) = (5-3)/2 = 1
Then, evaluate h of the result: h(1) = 2*1 + 3 = 5.
So (h*h^(-1))(5) = 5
This result can also be obtain by using the fact that the composition of the function and its inverse is an identity function. That is, applying the function to a value of x, and then applying the inverse will "undo" the function, resulting in the original value of x: (h*h^(-1))(x) = x

Math

the one-to-one functions g and h are defined as follows. g={(-4, -5), (1, 2), (7,1), (8, 5)} find the following: g^-1(1)= ----- h^-1(x)= (h * h^-1) (5)=

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