To obtain the iron in the blast furnace, carbon monoxide reduces iron (III) oxide & the hematite ore contains 45% of iron (III)oxide. How many kilograms of hematite ore required to produce 1000 kg...

To obtain the iron in the blast furnace, carbon monoxide reduces iron (III) oxide & the hematite ore contains 45% of iron (III)oxide. How many kilograms of hematite ore required to produce 1000 kg (one ton) of iron?  I'm mixed up and can't solve it. Also, can you tell me what is the difference between hematite ore and just iron III oxide?

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First let's look at the chemical equation for the production of iron from iron (III) oxide via a blast furnace.

Fe2O3 + 3CO --> 2Fe + 3CO2

They key piece of information here is that two moles of iron (III) oxide produce 2 moles of iron (Fe).  Now we need the molecular weights of both chemicals:

MW Fe: 55.85

MW Fe2O3: 159.69

Now we work from the end backwards.  Let's convert 1000 kg of iron to moles.

1000 kg * (1000 g/kg) * (mole/55.85 g) = 17905.1 moles...

(The entire section contains 237 words.)

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