A number from 1 to 10 is chosen at random. What is the probability of choosing a 5 or an even number?

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The numebers chosen are from 1 to 10.

Then possible outcomes are: 1,2,3,4,5,6,7,8,9,10

The probability of chosen a 5  OR and even number = probability of chosen a 5  + probability of chosen an even number.

Let us calculate each event:

P ( 5) = 1/10

Even number are: 2,4,6,8,10

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The numebers chosen are from 1 to 10.

Then possible outcomes are: 1,2,3,4,5,6,7,8,9,10

The probability of chosen a 5  OR and even number = probability of chosen a 5  + probability of chosen an even number.

Let us calculate each event:

P ( 5) = 1/10

Even number are: 2,4,6,8,10

==> P(even) = 5/10

Then :

P( 5 OR even) = P(5) + P(even)

                       = 1/10 + 5/10 = 6/10

                       = 3/5

==> P ( 5 or even) = 3/5

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