Note: Take East as the positive direction. A(n) 82 kg fisherman jumps from a dock into a 134 kg rowboat at rest on. . . the West side of the dock. If the velocity of the fisherman is 5 m/s to the...

Note: Take East as the positive direction. A(n) 82 kg fisherman jumps from a dock into a 134 kg rowboat at rest on. . .

the West side

of the dock. If the velocity of the fisherman is 5 m/s to

the West as he leaves the dock, what is the final velocity of the fisherman and the boat?

Answer in units of m/s

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ndnordic | High School Teacher | (Level 2) Associate Educator

Posted on

This is an inelastic collision where two separate objects become one after they hit.

the general equation is:

m1v1 + m2v2 = (m1+m2)v

where m1v1 are mass and velocity of object one; m2v2 are mass and velocity of object two; and v is the final velocity.

Here you have object one - the boat, and object two - the fisherman.

m1 = 134 kg, v1 = 0 (at rest)

m2 = 82 kg, v2 = 5 m/s

0 + 82 * 5 = 216v

v = 0.53 m/s

Sources:

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