Note: Take East as the positive direction. A(n) 82 kg fisherman jumps from a dock into a 134 kg rowboat at rest on. . .
the West side
of the dock. If the velocity of the fisherman is 5 m/s to
the West as he leaves the dock, what is the final velocity of the fisherman and the boat?
Answer in units of m/s
This is an inelastic collision where two separate objects become one after they hit.
the general equation is:
m1v1 + m2v2 = (m1+m2)v
where m1v1 are mass and velocity of object one; m2v2 are mass and velocity of object two; and v is the final velocity.
Here you have object one - the boat, and object two - the fisherman.
m1 = 134 kg, v1 = 0 (at rest)
m2 = 82 kg, v2 = 5 m/s
0 + 82 * 5 = 216v
v = 0.53 m/s