# I need someone to help me with this problems: 6/v=3/11, 16j=320, 13x=15-2x.

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Hello!

As I understand, there are three unconnected equations, each with its own variable. Let's solve them one by one.

**1)** `6/v = 3/11.`

This is a proportion and we can use a rule for solving it, but it is probably better to solve it step by step. First, multiply both sides by `v` (it cannot be zero, so such a multiplication gives an equivalent equation):

`6 = 3/11*v.`

Then multiply by `11:` `6*11 = 3*v.`

And finally divide by `3` and compute: `v = (6*11)/3 = 2*11 = 22.`

**2)** `16 j=320.`

Only one step is here, divide both sides by `16` and note that `320=32*10=2*16*10:`

`j=320/16=(2*16*10)/16=2*10=20.`

**3)** `13x=15-2x.`

Two steps are here: first, add `2x` to both sides and obtain `13x+2x=15,` or `15 x=15.` Second, divide both sides by `15` and obviously `x=1.`

Another quick way to solve the first equation (so that you don't have to deal with fractions) is to cross-multiply. Anytime you have an equation that is just fraction=fraction, cross-multiplication is a great quick way to clean things up.

So

`6/v = 3/11` becomes `3v = 6*11` or `3v = 66`

We now have a simple, one-step equation to solve. Divide both sides by 3 and you get

`v=22`