Need help solving for x (x-1)^3=8

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tgombar | Elementary School Teacher | (Level 1) Adjunct Educator

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The goal in this equation is the get the x by itself.  So, you need to take the cube root of both sides to eliminate the cube on the left side of your equation.  After you have done that, you are left with x-1=2.  You then add 1 to both sides of the equation in order to get x alone and you end up with x=3.

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chandrachaks | Elementary School Teacher | (Level 1) Adjunct Educator

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Following the procedure underneath we can calculate the value of x.

We are given the equation

(x-1)^3 = 8 and

8 is cube of 2.


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ajju | College Teacher | (Level 1) Adjunct Educator

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Given equation (x-1)^3=8

take cube root of both side

we get: (x - 1) = 2

or add 1 both side

x - 1 + 1 = 2 +1

x = 3

then answer is x = 3

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rsarvar1a | Student, Grade 9 | (Level 1) Honors

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We have the equation:

(x-1)^3 = 8

We know that both sides of this equation are actually cubes. So, we can simplify this equation by cube-rooting both sides of this equation:

cube root of [(x-1)^3] = cube root of 8

On the left side, the cube root cancels out the ^3. So, we get x-1 on the left side. On the right side, the cube root of 8 is 2:

x - 1 = 2

Now, all we have to do is move the - 1 to the right side using inverse operations:

x - 1 + 1 = 2 + 1

x = 3

Therefore, x = 3.

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