# I need help solving a math problem. Solve. `(x-2.3)^2=25`

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### 2 Answers

`(x-2.3)^2=25`

To solve, eliminate the exponent 2. So, take the square root of both sides.

`sqrt(x-2.3)^2=+-sqrt25`

`x-2.3=+-5`

Then, isolate x. To do so, add both sides by 2.3.

`x+2.3-2.3=+-5+2.3`

x=+-5+2.3

And, compute for the values of x.

`x=5+2.3=7.3 ` and `x=-5+2.3=-2.7`

**Hence, the solutions are `x=-2.7` and `x=7.3` .**

Hi, user5932103,

I assume the problem is:

**(x-2.3)^2 = 25**

There are a couple of ways to do this problem. The way I would do it is, first, take the square root of each sides. That gives you:

**x-2.3 = +-5**, meaning positive 5 and negative 5.

For this, we separate the equation into two equations:

**x-2.3 = 5 and x-2.3 = -5**

Solving these, we add 2.3 to all sides, giving us:

**x = 7.3 x = -2.7**

So, there would be two solutions.

Good Luck, user5932103. I hope this helps.