# co-efficient of kinetic friction If you use a horizontal force of 30N(newton) to slide a 12kg wooden crate across the floor at a constant velocity what is the coefficient of kinetic friction...

co-efficient of kinetic friction

If you use a horizontal force of 30N(newton) to slide a 12kg wooden crate across the floor at a constant velocity what is the coefficient of kinetic friction between the crate and the floor?

I heard this but i'm not too sure if the formula was

Kinetic force = F/N or something, anyways here's the problem

I would appreciate if the work is shown, i need to know how to solve this

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When you slide the wooden crate along the floor the kinematic friction will act against the direction of travelling.Since the crate is travelling at a constant speed without acceleration the forces acting on it are at a equilibrium state. This is also related to Newton's first law.

Sliding force `=` Friction force (F)

`30N = F`

Friction force (F) is given as a product of normal force(N) and coefficient of kinetic friction(`mu` ).

`F = mu*N`

`mu = F/R`

`= 30/(12*9.81)`

`= 0.255`

*So the coefficient of kinetic friction is 0.255.*