# Need help finding the limit as h approaches 0 for f(a)= [(-2)] / [(a+1)(a+h+1)]

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Student Comments

william1941 | Student

The solution for f(a) = -2/[(a+1)(a+h+1)] for limit h --> 0. can be found by merely substituting h=0. If the result is defined, that is the required solution.

-2/[(a+1)(a+h+1)]

substitute h=0

=>-2/[(a+1)(a+0+1)]

=>-2/[(a+1)(a+1)]

=>-2/(a+1)^2

Now, -2/(a+1)^2 is defined.

**Therefore : -2/[(a+1)(a+h+1)] for limit h --> 0 = -2/(a+1)^2**

neela | Student

To find the limit of f(a) = {-2/[(a+1)(a+h+1)} as h --> 0.

Solution:

Put h = 0 in f(a) = -2/[(a+1)(a+0+1)]

f(a) = -2/[(a+1)(a+1)].

f(a) = -2/(a+1)^2.

Also, for any h = 0+ , f(a) = -2/(a+1)(a+1) = -2/(a+1)^2.

For any h = 0- , f(a) = -2/(a+1)^2.

Therefore, Lt f(a) = lt-2/[(a+1)(a+h-1)] as h - -> 0 is -2/(a+1)^2.