# I need a calculus review...my mid-term exam is in 1.5 hours...HELP?!? please?I need formula's and review on: points of discontinuity, domain and range, limits, horizontal asymptotes, continuous...

I need a calculus review...my mid-term exam is in 1.5 hours...HELP?!? please?

I need formula's and review on: points of discontinuity, domain and range, limits, horizontal asymptotes, continuous functions, period and amplitute, finding half-life, slope between points, derivatives, equatiions of line to cuves (tangent lines) and position, velocity and accelleration

also, theres something i've never seen before...

e.g. cscx=2.3 on [0,2π]     (π is pi) what is this and how do i solve it?

neela | High School Teacher | (Level 3) Valedictorian

Posted on

cscx = 2.3 on (0, 2pi)

To solve for x:

Solution:

I hope you want to solve cosecx = 2.3.

But cosecx =1/sinx =2.3. Therefore,

sinx = 1/2.3

So x= arcsin(1/2.3) = 25.77146172 degree aaaapproximately.

Also x=25.7715+180 = 205.77146172 degree.