# I need to calculate the change in thermal energy when 230g of water warms from 12degrees C to 90 degrees C.

*print*Print*list*Cite

Change in thermal energy= 230* (difference in temperature)

= 230* (90-12)

= 230*78

= 17940 calories (or cal)

H=MST

M=MASS OF WATER

S=SPECIFIC HEAT

T=CHANGE OF TEMPERATURE

SO YOUR ANSWER IS

H(HEAT)={230x1x(90-12)}cal

=(230x1x78)cal

=17940 cal

Thermal energy is measured in units of calorie, where 1 calorie is defined as the amount of thermal energy required to raise the temperature of 1 gram of water by 1 degree C. Also the total thermal energy required to raise the temperature of a given mass of water (m), from initial temperature (t1) to a higher temperature (t2) is given by the formula:

Thermal energy in calories = m*((t2 - t1)

It is given:

m = 230 g

t1 = 12 degrees C

t2 = 90 degrees C

Substituting these given values in equation for thermal energy we get:

Thermal energy = 230*(90 - 12) = 230*78 = 17940 calories

The change in thermal energy of water is same as the thermal energy used for raising its temperature.

Answer:

Change in thermal energy = 17940 calories.