I am unsure what you are asking for, however I will assume you are asking`n+5n=?`

To solve this you must search for all like terms, in this case the two monomials n and 5n. The blank space in front of the solitary n is actually a 1, as we still consider there to be one n in the problem. If we insert this 1 we get: `1n+5n=?`

When adding monomials, add their constants together, in this case 1 and 5. Adding these together you get 6n as your answer.

`1n+5n=(1+5)n=6n`

The reason the n does not become squared or anything else strange is, due to it being a variable, we actually aren't sure what the value is. We can only manipulate the constants the variable is multiplied by. Hope that helps!

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If n=1/6 then you are assuming the original equation given was `n+5n=1`

Since that was not given I would be careful about including that as an answer.

To solve this, you should know that n without a coefficient in front of it actually has the coefficient of 1--Also known as 1n. So,

1n + 5n = 6n since you add the coefficients together. Therefore, the answer is 6n.