Mr. Jones has a female student to male student ratio of 4:3. He has 12 boys. Ms.brown has the same number of students in her class, but a female to male ratio of 5:9. She has 18 boys in her class. Which class had more females?
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In Mr. Jones class, the female to male ratio is 4:3. So, the equation is:
`F/M = 4/3`
Since he has 12 boys, plugging in M=12, it becomes:
Isolating the F yields:
Hence, in Mr. Jones' class there are 16 girls.
In Ms. Brown's class, the female to male ratio is 5:9. So, the equation is:
Since she has 18 boys in her class, plug-in M=18.
And, isolate the F.
Thus, there are 10 girls in Ms. Brown's class.
Therefore, Mr. Jones' class has more female students.
Mr. Jones' class has 4x female and 3x male student.
3x = 12, so x = 4.
So he has 4(4) = 16 female students in his class.
He has 12 + 16 = 28 students altogether.
Ms. brown has 28 students as well, but 5y female and 9y male students.
9y = 18 so y = 2.
So she has 5(2) = 10 female students in her class.
Thus, Mr. Jones has more female students in his class.
Thank you so much for your help, I understand now
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