# Mr. Jones has a female student to male student ratio of 4:3. He has 12 boys. Ms.brown has the same number of students in her class, but a female to male ratio of 5:9. She has 18 boys in her class....

Mr. Jones has a female student to male student ratio of 4:3. He has 12 boys. Ms.brown has the same number of students in her class, but a female to male ratio of 5:9. She has 18 boys in her class. Which class had more females?

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In Mr. Jones class, the female to male ratio is 4:3. So, the equation is:

`F/M = 4/3`

Since he has 12 boys, Â plugging in M=12, it becomes:

`F/12=4/3`

Isolating the F yields:

`F=(12*4)/3`

`F=16`

Hence, in Mr. Jones' class there are 16 girls.

In Ms. Brown's class, the female to male ratio is 5:9. So, the equation is:

`F/M=5/9`

Since she has 18 boys in her class, plug-in M=18.

`F/18=5/9`

And, isolate the F.

`F=(18*5)/9`

`F=10`

Thus, there are 10 girls in Ms. Brown's class.

**Therefore, Mr. Jones' class has more female students.**

Mr. Jones' class has 4x female and 3x male student.

3x = 12, so x = 4.

**So he has 4(4) = 16 female students in his class.**

He has 12 + 16 = 28 students altogether.

Ms. brown has 28 students as well, but 5y female and 9y male students.

9y = 18 so y = 2.

**So she has 5(2) = 10 female students in her class.**

Thus, Mr. Jones has more female students in his class.