A motorbike and a car leave a service station at the same time. The motorbike travels on a bearing of 080`@` and the car travles for 15.7km on a bearing on 108 degrees until the bearing of the motorbike from the car is 310 degrees. How far correct to 1 decimal place, has the motorbike travelled?
The answer is 7.7km
Let S be the position of the service station (please refer to the attached image), B be the position of the bike and C be the position of the car.
Given SC=`15.7` Km. Let SB=`x` Km
Applying the sine rule:
`rArr x=7.67~~7.7 Km`
Therefore, the motorbike has travelled a distance of 7.7 Km.
How did you get 50 degrees?