A vehicle with a mass 1.5*10^3 kg is accelerated from rest and reaches a velocity of 15 m/s in 6 seconds. The acceleration of the vehicle during the 6 seconds that leads to this increase in speed is equal to (15 - 0)/6 = 2.5 m/s^2.

The distance traveled by...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

A vehicle with a mass 1.5*10^3 kg is accelerated from rest and reaches a velocity of 15 m/s in 6 seconds. The acceleration of the vehicle during the 6 seconds that leads to this increase in speed is equal to (15 - 0)/6 = 2.5 m/s^2.

The distance traveled by the body during the 6 seconds is given by D = 0*6 + (1/2)*2.5*36 = 45 m

To accelerate a body weighing 1.5*10^3 kg by 2.5 m/s^2 a force of 3.75*10^3 N is required. The work done while the force is applied for a distance of 45 m is 45*3.75*10^3 J. As the work is done in a duration of time equal to 6 seconds, the power is equal to 28.125 kW

The output of power by the car in the 6 seconds is equal to 28.125 kW.

**Further Reading**