Let's first obtain the volume at both temperatures using the relationship Volume = Mass/Density.

At 0 degrees C (`V_1`e have:

`V_1` = `(3.250 g)/(13.596 g/(cm^3))` = .2390 `cm^3` ` `

At 25 degrees C (`V_2`e have:

`V_2` = `(3.250 g)/(13.534 g/(cm^3))` = .2401 `cm^3`

We will think of the column of mercury inside the capillary as a...

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Let's first obtain the volume at both temperatures using the relationship Volume = Mass/Density.

At 0 degrees C (`V_1`e have:

`V_1` = `(3.250 g)/(13.596 g/(cm^3))` = .2390 `cm^3` ` `

At 25 degrees C (`V_2`e have:

`V_2` = `(3.250 g)/(13.534 g/(cm^3))` = .2401 `cm^3`

We will think of the column of mercury inside the capillary as a cylinder. The height of the cylinder is given by the formula

`h = V/(pi * r^2)`

The radius, r, in centimeters is `(0.180 mm) / 2 * (1 cm)/(10 mm)` or .009 cm. Therefore, at 0 degrees, the height is:

`h_1` =`(.2390 cm^3)/(pi*(.009 cm)^2)` = 939.2 `cm`

` `

At 25 degrees C, the height is:

`h_2 =``(.2401 cm^3)/(pi*(.009 cm)^2) = 943.5 cm`

Subtracting these two, 943.5 cm - 939.2 cm, we obtain a rise in mercury **height of 4.3 cm**, the final answer.

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