In order to find the x and y intercepts on a graph, you will need to know how to work with slope-intercept form, y=mx + b in which m is the slope and b is the y intercept, or point at which the linear equation crosses the y-axis.
For question 1, x/2 means 1/2 x times 6 so the slope is 1/2 * 6/1 which would be 1/2 of 6 or 3. or rise over run 3/1 (up 3 units, over right 1 unit and plot a point)
The y-intercept is at 0.
Another simple way to find the answer without graphing is to set your x value = 0 in order to find your y-intercept, so anything times 0=0 (zero property).
For the x-intercept, set your y value = 0 and solve for x, giving you 0.
For question 2, in slope-intercept form, you would rewrite it as y=-2x+5. By applying the same rules, your x intercept would make your y value=0 and solve for x by subtracting 5 from both sides of the equation and then divide by -2. -5/-2 would yield 2 1/2 (two and one half) for your x intercept.
Your y-intercept would be found by setting your x =0, so you would have 5-0 or 5.
On a graph, the x-intercept is the point when y = 0, and the y-intercept is the point when x = 0.
For #1, y = (x/2)*6, if you plug in 0 for x, y = (0/2)*6 = 0, so the y-intercept is 0. If you plug in 0 for y, 0 = (x/2)*6. To solve for x, divide by 6 and multiply by 2. You get x = 0, so the x-intercept is 0.
For #2, y = 5 - 2x, if you plug in 0 for x, y = 5 - 2(0) = 5, so the y-intercept is 5. Notice if you write the equation in y = mx + b form, y = -2x + 5, 5 is in the place of b, the y-intercept. FOr the x-intercept, if you plug in 0 for y, 0 = 5 - 2x. Solve for x by subtracting 5 from 0 and then dividing by -2. You get x = 5/2. So, the x-intercept is 5/2.
1) y= (x/2)*6
To get the x intercept, sub y=0. X would also be 0
To get y intercept, sub. x=0. Y would also be 0
So, line passes through origin in a linear relationship.
2) y= 5-2x
To get x-intercept, sub y=0
To get y-intercept, sub. x=0